platform: recalculate heap size to support new tlb entry number

Previous patch introduced a change that using hart count as the default
number of tlb entries in the fifo. This makes the default tlb fifo size
grow in square with the number of harts. So the default heap size is
not enough to allocate tlb fifo when the hart count is big.

Fixes: 52fd64b ("platform: Uses hart count as the default size of tlb info")
Signed-off-by: Inochi Amaoto <inochiama@outlook.com>
Reviewed-by: Anup Patel <anup@brainfault.org>
This commit is contained in:
Inochi Amaoto
2023-12-10 17:44:54 +08:00
committed by Anup Patel
parent a25fc74699
commit 87aa3069d1
4 changed files with 19 additions and 3 deletions

View File

@@ -10,7 +10,9 @@
#include <libfdt.h>
#include <platform_override.h>
#include <sbi/riscv_asm.h>
#include <sbi/sbi_bitops.h>
#include <sbi/sbi_hartmask.h>
#include <sbi/sbi_heap.h>
#include <sbi/sbi_platform.h>
#include <sbi/sbi_string.h>
#include <sbi/sbi_system.h>
@@ -54,6 +56,18 @@ static void fw_platform_lookup_special(void *fdt, int root_offset)
}
}
static u32 fw_platform_calculate_heap_size(u32 hart_count)
{
u32 heap_size;
heap_size = SBI_PLATFORM_DEFAULT_HEAP_SIZE(hart_count);
/* For TLB fifo */
heap_size += 0x40 * (hart_count) * (hart_count);
return BIT_ALIGN(heap_size, HEAP_BASE_ALIGN);
}
extern struct sbi_platform platform;
static bool platform_has_mlevel_imsic = false;
static u32 generic_hart_index2id[SBI_HARTMASK_MAX_BITS] = { 0 };
@@ -115,7 +129,7 @@ unsigned long fw_platform_init(unsigned long arg0, unsigned long arg1,
}
platform.hart_count = hart_count;
platform.heap_size = SBI_PLATFORM_DEFAULT_HEAP_SIZE(hart_count);
platform.heap_size = fw_platform_calculate_heap_size(hart_count);
platform_has_mlevel_imsic = fdt_check_imsic_mlevel(fdt);
/* Return original FDT pointer */