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scripts: Add Kconfiglib v14.1.0 under scripts directory

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We adopt Kconfiglib v14.1.0 sources under scripts directory so that
top-level OpenSBI makefile can directly use Kconfiglib scripts without
expecting users to install a particular version of Kconfiglib on their
build system.

Signed-off-by: Anup Patel <apatel@ventanamicro.com>
Tested-by: Andrew Jones <ajones@ventanamicro.com>
Acked-by: Atish Patra <atishp@rivosinc.com>
Tested-by: Atish Patra <atishp@rivosinc.com>
This commit is contained in:
Anup Patel
2022-08-08 09:33:03 +05:30
committed by Anup Patel
parent b9edf49b67
commit 422f0e0486
11 changed files with 11156 additions and 0 deletions
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scripts/Kconfiglib/oldconfig.py Executable file
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#!/usr/bin/env python3
# Copyright (c) 2018-2019, Ulf Magnusson
# SPDX-License-Identifier: ISC
"""
Implements oldconfig functionality.
1. Loads existing .config
2. Prompts for the value of all modifiable symbols/choices that
aren't already set in the .config
3. Writes an updated .config
The default input/output filename is '.config'. A different filename can be
passed in the KCONFIG_CONFIG environment variable.
When overwriting a configuration file, the old version is saved to
<filename>.old (e.g. .config.old).
Entering '?' displays the help text of the symbol/choice, if any.
Unlike 'make oldconfig', this script doesn't print menu titles and comments,
but gives Kconfig definition locations. Printing menus and comments would be
pretty easy to add: Look at the parents of each item, and print all menu
prompts and comments unless they have already been printed (assuming you want
to skip "irrelevant" menus).
"""
from __future__ import print_function
import sys
from kconfiglib import Symbol, Choice, BOOL, TRISTATE, HEX, standard_kconfig
# Python 2/3 compatibility hack
if sys.version_info[0] < 3:
input = raw_input
def _main():
# Earlier symbols in Kconfig files might depend on later symbols and become
# visible if their values change. This flag is set to True if the value of
# any symbol changes, in which case we rerun the oldconfig to check for new
# visible symbols.
global conf_changed
kconf = standard_kconfig(__doc__)
print(kconf.load_config())
while True:
conf_changed = False
for node in kconf.node_iter():
oldconfig(node)
if not conf_changed:
break
print(kconf.write_config())
def oldconfig(node):
"""
Prompts the user for a value if node.item is a visible symbol/choice with
no user value.
"""
# See main()
global conf_changed
# Only symbols and choices can be configured
if not isinstance(node.item, (Symbol, Choice)):
return
# Skip symbols and choices that aren't visible
if not node.item.visibility:
return
# Skip symbols and choices that don't have a prompt (at this location)
if not node.prompt:
return
if isinstance(node.item, Symbol):
sym = node.item
# Skip symbols that already have a user value
if sym.user_value is not None:
return
# Skip symbols that can only have a single value, due to selects
if len(sym.assignable) == 1:
return
# Skip symbols in choices in y mode. We ask once for the entire choice
# instead.
if sym.choice and sym.choice.tri_value == 2:
return
# Loop until the user enters a valid value or enters a blank string
# (for the default value)
while True:
val = input("{} ({}) [{}] ".format(
node.prompt[0], _name_and_loc_str(sym),
_default_value_str(sym)))
if val == "?":
_print_help(node)
continue
# Substitute a blank string with the default value the symbol
# would get
if not val:
val = sym.str_value
# Automatically add a "0x" prefix for hex symbols, like the
# menuconfig interface does. This isn't done when loading .config
# files, hence why set_value() doesn't do it automatically.
if sym.type == HEX and not val.startswith(("0x", "0X")):
val = "0x" + val
old_str_val = sym.str_value
# Kconfiglib itself will print a warning here if the value
# is invalid, so we don't need to bother
if sym.set_value(val):
# Valid value input. We're done with this node.
if sym.str_value != old_str_val:
conf_changed = True
return
else:
choice = node.item
# Skip choices that already have a visible user selection...
if choice.user_selection and choice.user_selection.visibility == 2:
# ...unless there are new visible symbols in the choice. (We know
# they have y (2) visibility in that case, because m-visible
# symbols get demoted to n-visibility in y-mode choices, and the
# user-selected symbol had visibility y.)
for sym in choice.syms:
if sym is not choice.user_selection and sym.visibility and \
sym.user_value is None:
# New visible symbols in the choice
break
else:
# No new visible symbols in the choice
return
# Get a list of available selections. The mode of the choice limits
# the visibility of the choice value symbols, so this will indirectly
# skip choices in n and m mode.
options = [sym for sym in choice.syms if sym.visibility == 2]
if not options:
# No y-visible choice value symbols
return
# Loop until the user enters a valid selection or a blank string (for
# the default selection)
while True:
print("{} ({})".format(node.prompt[0], _name_and_loc_str(choice)))
for i, sym in enumerate(options, 1):
print("{} {}. {} ({})".format(
">" if sym is choice.selection else " ",
i,
# Assume people don't define choice symbols with multiple
# prompts. That generates a warning anyway.
sym.nodes[0].prompt[0],
sym.name))
sel_index = input("choice[1-{}]: ".format(len(options)))
if sel_index == "?":
_print_help(node)
continue
# Pick the default selection if the string is blank
if not sel_index:
choice.selection.set_value(2)
break
try:
sel_index = int(sel_index)
except ValueError:
print("Bad index", file=sys.stderr)
continue
if not 1 <= sel_index <= len(options):
print("Bad index", file=sys.stderr)
continue
# Valid selection
if options[sel_index - 1].tri_value != 2:
conf_changed = True
options[sel_index - 1].set_value(2)
break
# Give all of the non-selected visible choice symbols the user value n.
# This makes it so that the choice is no longer considered new once we
# do additional passes, if the reason that it was considered new was
# that it had new visible choice symbols.
#
# Only giving visible choice symbols the user value n means we will
# prompt for the choice again if later user selections make more new
# choice symbols visible, which is correct.
for sym in choice.syms:
if sym is not choice.user_selection and sym.visibility:
sym.set_value(0)
def _name_and_loc_str(sc):
# Helper for printing the name of the symbol/choice 'sc' along with the
# location(s) in the Kconfig files where it is defined. Unnamed choices
# return "choice" instead of the name.
return "{}, defined at {}".format(
sc.name or "choice",
", ".join("{}:{}".format(node.filename, node.linenr)
for node in sc.nodes))
def _print_help(node):
print("\n" + (node.help or "No help text\n"))
def _default_value_str(sym):
# Returns the "m/M/y" string in e.g.
#
# TRISTATE_SYM prompt (TRISTATE_SYM, defined at Kconfig:9) [n/M/y]:
#
# For string/int/hex, returns the default value as-is.
if sym.type in (BOOL, TRISTATE):
return "/".join(("NMY" if sym.tri_value == tri else "nmy")[tri]
for tri in sym.assignable)
# string/int/hex
return sym.str_value
if __name__ == "__main__":
_main()